SYSTEM OF EQUATIONS WITH INFINITELY MANY SOLUTIONS

Two linear equations in a system are exactly the same, then the system has infinitely many solution.

Consider the following system of equations.

3x - y + 5 = 0 ----(1)

15x - 5y + 25 = 0 ----(2)

Divide both sides of the equation (2) by 5.

(2) ÷ 5 ----> 15x/5 - 5y/5 + 25/5 = 0/5

3x - y + 5 = 0

When you divide the equation (2) by 5, you get the equation (1).

So, the two equations given in the above system are exactly same. Hence the system has infinitely many solutions.

The other way to check whether a system of linear equations in two variables has infinitely many solutions is writing the equations in slope intercept form.

Consider the following system of equations given in slope-intercept form.

y = m1x + b1

(slope = m1 and y-intercept = b1)

y = m2x + b2

(slope = m2 and y-intercept = b2)

If the above system of equations has infinitely many solutions, then it has to satisfy the following two conditions.

m1 = m2

b1 = b2

The lines are same and hence they coincide.

Since the lines coincide, they touch each other in all the points on both the lines and the system has infinitely many solutions.

Note :

If the system of linear equations is given in general form or standard form, write them in slope-intercept form and proceed as explained above.

General Form :

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Standard Form :

a1x + b1y = c1

a2x + b2y = c2

Examples 1-5 : Determine whether the following systems of linear equations have infinitely many solutions.

Example 1 :

y = 3x + 5

y = 3x + 5

Solution :

y = 3x + 5 ----> m = 3 and b = 5

y = 3x + 5 ----> m = 3 and b = 5

In the above two linear equations, both the slopes and y-intercepts are same.

So, the lines coincide and they  touch each other in all the points on the line.

Hence, the system has infinitely many solution.

Example 2 :

y = -2x - 5

y = -2x + 1

Solution :

y = -2x - 5 ----> m = -2 and b = -5

y = -2x + 1 ----> m = -2 and b = 1

In the above two linear equations, the slopes are equal, but y-intercepts are different.

So, the lines do not coincide.

Hence, the system does not have infinitely many solution.

Example 3 :

y = 3x - 2 

3y = 9x

Solution :

y = 3x - 2 ----> m = 3 and b = -2

The second equation 3y = 9x is not in slope intercept form. Divide both sides by 3 to get the equation in slope- intercept form.

y = 3x

y = 3x ----> m = 3 and b = 0

In the given two linear equations, the slopes are equal, but y-intercepts are different.

So, the lines do not coincide.

Hence, the system does not have infinitely many solution.

Example 4 :

4x + 2y - 1 = 0

2x + y - 0.5 = 0

Solution :

The equations are not in slope-intercept form.

Write them in slope-intercept form.

4x + 2y - 1 = 0

2y = -4x + 1

y = -2x + 1/2

2x + y - 0.5 = 0

y = -2x + 0.5

y = -2x + 1/2

y = -2x + 1/2 ----> m = -2 and b = 1/2

y = -2x + 1/2 ----> m = -2 and b = 1/2

In the given two linear equations, both the slopes and y-intercepts are same.

So, the lines coincide and they  touch each other in all the points on the line.

Hence, the system has infinitely many solution.

Example 5 :

2x - y = 1

4x + y = 5

Solution :

The equations are not in slope-intercept form.

Write them in slope-intercept form.

2x - y = 1

-y = -2x + 1

y = 2x - 1 ---> m = 2

4x + y = 5

y = -4x + 5 ----> m = -4

In the given two linear equations, the slope are different.

So, the lines do not coincide.

Hence, the system does not have infinitely many solutions.

Example 6 :

In the following system of linear equations, k is a constant and x and y are variables. For what value of k will the system of equations have infinitely many solution?

kx - 3y = 12

4x - 5y = 20

Solution :

The equations are not in slope-intercept form.

Write them in slope-intercept form.

kx - 3y = 12

-3y = -kx + 12

3y = kx - 12

y = (k/3)x - 4

4x - 5y = 20

-5y = -4x + 20

5y = 4x - 20

y = (4/5)x - 4

y = (k/3)x - 4 ----> m = k/3 and b = -4

y = (4/5)x - 4 ----> m = 4/5 and b = -4

In the given two linear equations, y-intercepts are equal.

If slopes also are equal, then the lines will coincide and the system will have infinitely many solutions.

It is given that the system has infinitely many solutions.

So, the slopes must be equal.

k/3 = 4/5

Multiply both sides by 3.

k = 12/5

When k = 12/5, the system will have infinitely many solutions.

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