Intercept form equation of a parabola is
y = a(x - p)(x - q)
To find the x-intercepts of the parabola above, substitute y = 0.
a(x - p)(x - q) = 0
Divide both sides by a.
(x - p)(x - q) = 0
x - p = 0 or x - q = 0
x = p or x = q
The two x-intercepts of the parabola y = a(x - p)(x - q) are p and q.
To find the x-coordinate of the vertex, find the average of the two x-intercepts.
x = (p + q)/2
After having found the x-coordinate, you can substitute it into the equation of the parabola and find the y-coordinate of the vertex.
Examples 1-4 : Write the following equations of parabolas in intercept form.
Example 1 :
Write the following equation of parabola in intercept form.
y = x2 - 5x + 6
Solution :
y = x2 - 5x + 6
Factor the quadratic expression x2 - 5x + 6.
In the quadratic expression above, the coefficient of x2 is 1. So, get two factors of the constant term '+6' such that the sum of the two factors is equal to the coefficient of x, that is '-5'.
Then the two factors of '+6' are '-2' and '-3'.
Now, split the middle term -5x using the two factors -2 and -3.
x2 - 5x + 6 :
= x2 - 2x - 3x + 6
= x(x - 2) - 3(x - 3)
= (x - 2)(x - 3)
Therefore, the intercept form equation of the parabola is
y = (x - 2)(x - 3)
Example 2 :
y = x2 - 5x - 24
Solution :
y = x2 - 5x - 24
Factor the quadratic expression x2 - 5x - 24.
In the quadratic expression above, the coefficient of x2 is 1. So, get two factors of the constant term '-24' such that the sum of the two factors is equal to the coefficient of x, that is '-5'.
Then the two factors of '-24' are '-8' and '+3'.
Now, split the middle term -5x using the two factors -8 and +3.
x2 - 5x - 24 :
= x2 - 8x + 3x - 24
= x(x - 8) + 3(x - 8)
= (x - 8)(x + 3)
Therefore, the intercept form equation of the parabola is
y = (x - 8)(x + 3)
Example 3 :
y = 2x2 - 12x + 16
Solution :
y = 2x2 - 12x + 16
Factor 2.
y = 2(x2 - 6x + 8)
Factor the quadratic expression x2 - 6x + 8.
In the quadratic expression above, the coefficient of x2 is 1. So, get two factors of the constant term '+8' such that the sum of the two factors is equal to the coefficient of x, that is '-6'.
Then the two factors of '+8' are '-2' and '-4'.
Now, split the middle term -6x using the two factors -2 and -4.
x2 - 6x + 8 :
= x2 - 2x - 4x + 8
= x(x - 2) - 4(x - 2)
= (x - 2)(x - 4)
Therefore, the intercept form equation of the parabola is
y = 2(x - 2)(x - 3)
Example 4 :
y = 2x2 + 11x + 12
Solution :
y = 2x2 + 11x + 12
Here, the coefficient of x2 is 2. But, 2 can not be factored from the expression 2x2 + 11x + 12 as we have done in the previous example.
So, we have to factor the expression 2x2 + 11x + 12 as it is.
Multiply the coefficient of x2 and the constant term 12.
2x12 = 24
Now, get two factors of '+24' such that the sum of the two factors is equal to the coefficient of x, that is '+11'.
Then the two factors of '+24' are '+3' and '+8'.
Now, split the middle term +11x using the two factors +3 and +8.
2x2 + 11x + 12 :
= 2x2 + 8x + 3x + 12
= 2x(x + 4) + 3(x + 4)
= (x + 4)(2x + 3)
= (2x + 3)(x + 4)
= 2(x + 3/2)(x + 4)
Therefore, the intercept form equation of the parabola is
y = = 2(x + 3/2)(x + 4)
Example 5 :
Find the vertex of the parabola :
y = -3(x + 2)(x - 6)
Solution :
y = -3(x + 2)(x - 6)
Substitute y = 0 to find the x-intercepts of the parabola above,
-3(x + 2)(x - 6) = 0
Divide both sides by -3.
-3(x + 2)(x - 6) = 0
x + 2 = 0 or x - 6 = 0
x = -2 or x = 6
x-coordinate of the vertex :
x = (-2 + 6)/2
x = 4/2
x = 2
y-coordinate of the vertex :
Substitute x = 2 in y = -3(x + 2)(x - 6).
y = -3(2 + 2)(2 - 6)
y = -3(4)(-4)
y = 48
Vertex of the parabola is (2, 48).
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
May 05, 24 12:25 AM
May 03, 24 08:50 PM
May 02, 24 11:43 PM