Problems 1-8 : Find the vertex of the parabola.
Problem 1 :
y = x2 - 2x - 5
Problem 2 :
y = -x2 - 14x - 59
Problem 3 :
y = x2 + 4x
Problem 4 :
x = y2 - 2y - 5
Problem 5 :
x = -y2 - 14y - 59
Problem 6 :
x = y2 + 4y
Problem 7 :
y = -3(x + 2)(x - 6)
Problem 8 :
y = 2x(x - 3)
Problems 8-10 : Write the equation of the parabola in vertex form and find the vertex from it.
Problem 9 :
y = x2 - 6x + 10
Problem 10 :
x = -y2 - 12y - 40
1. Answer :
Comparing y = ax2 + bx + c and y = x2 - 2x - 5,
a = 1, b = -2 and c = -5
x-coordinate of the vertex :
x = -b/2a
Substitute a = 1 and b = -2.
x = -(-2)/2(1)
x = 2/2
x = 1
y-coordinate of the vertex :
Substitute x = 1 in y = x2 - 2x - 5.
y = 12 - 2(1) - 5
y = 1 - 2 - 5
y = -6
Vertex of the parabola is (1, -6).
2. Answer :
Comparing y = ax2 + bx + c and y = -x2 - 14x - 59,
a = -1, b = -14 and c = -59
x-coordinate of the vertex :
x = -b/2a
Substitute a = -1 and b = -14.
x = -(-14)/2(-1)
x = 14/(-2)
x = -7
y-coordinate of the vertex :
Substitute x = -7 in y = -x2 - 14x - 59.
y = -(-7)2 - 14(-7) - 59
y = -49 + 98 - 59
y = -10
Vertex of the parabola is (-7, -10).
3. Answer :
Comparing y = ax2 + bx + c and y = x2 + 4x,
a = 1, b = 4 and c = 0
x-coordinate of the vertex :
x = -b/2a
Substitute a = 1 and b = 4.
x = -4/2(1)
x = -4/2
x = -2
y-coordinate of the vertex :
Substitute x = -2 in y = x2 + 4x.
y = (-2)2 + 4(-2)
y = 4 - 8
y = -4
Vertex of the parabola is (-2, -4).
4. Answer :
Comparing x = ay2 + by + c and x = y2 - 2y - 5,
a = 1, b = -2 and c = -5
y-coordinate of the vertex :
y = -b/2a
Substitute a = 1 and b = -2.
y = -(-2)/2(1)
y = 2/2
y = 1
x-coordinate of the vertex :
Substitute y = 1 in x = y2 - 2y - 5.
x = 12 - 2(1) - 5
x = 1 - 2 - 5
x = -6
Vertex of the parabola is (-6, 1).
5. Answer :
Comparing x = ay2 + by + c and x = -y2 - 14y - 59,
a = -1, b = -14 and c = -59
x-coordinate of the vertex :
y = -b/2a
Substitute a = -1 and b = -14.
y = -(-14)/2(-1)
y = 14/(-2)
y = -7
y-coordinate of the vertex :
Substitute y = -7 in x = -y2 - 14y - 59.
x = -(-7)2 - 14(-7) - 59
x = -49 + 98 - 59
x = -10
Vertex of the parabola is (-10, -7).
6. Answer :
Comparing x = ay2 + by + c and x = y2 + 4y,
a = 1, b = 4 and c = 0
x-coordinate of the vertex :
y = -b/2a
Substitute a = 1 and b = 4.
y = -4/2(1)
y = -4/2
y = -2
y-coordinate of the vertex :
Substitute y = -2 in x = y2 + 4y.
x = (-2)2 + 4(-2)
x = 4 - 8
x = -4
Vertex of the parabola is (-4, -2).
7. Answer :
y = -3(x + 2)(x - 6)
Substitute y = 0 to find the x-intercepts of the parabola above.
-3(x + 2)(x - 6) = 0
Divide both sides by -3.
-3(x + 2)(x - 6) = 0
x + 2 = 0 or x - 6 = 0
x = -2 or x = 6
x-coordinate of the vertex :
x = (-2 + 6)/2
x = 4/2
x = 2
y-coordinate of the vertex :
Substitute x = 2 in y = -3(x + 2)(x - 6).
y = -3(2 + 2)(2 - 6)
y = -3(4)(-4)
y = 48
Vertex of the parabola is (2, 48).
8. Answer :
y = 2x(x - 3)
To find the x-intercepts of the parabola above, substitute y = 0.
2x(x - 3) = 0
Divide both sides by 2.
x(x - 3) = 0
x = 0 or x = 3
x-coordinate of the vertex :
x = (0 + 3)/2
x = 3/2
x = 1.5
y-coordinate of the vertex :
Substitute x = 1.5 in y = 2x(x - 3).
y = 2(1.5)(1.5 - 3)
y = 2(1.5)(-1.5)
y = -4.5
Vertex of the parabola is (1.5, -4.5).
9. Answer :
y = x2 - 6x + 10
y = x2 - 2(x)(3) + 32 - 32 + 10
Using the identity (a - b)2 = a2 - 2ab + b2,
y = (x - 3)2 - 32 + 10
y = (x - 3)2 - 9 + 10
y = (x - 3)2 + 1
Comparing y = a(x - h)2 + k and y = (x - 3)2 + 1,
h = 3 and k = 1
Vertex of the parabola :
(h, k) = (3, 1)
10. Answer :
x = -y2 - 12y - 40
x = -1(y2 + 12y) - 40
x = -1[y2 + 2(y)(6) + 62 - 62] - 40
Using the identity (a + b)2 = a2 + 2ab + b2,
x = -1[(y + 6)2 - 62] - 40
x = -1[(y + 6)2 - 36] - 40
x = -1(y + 6)2 + 36 - 40
x = -1(y + 6)2 - 4
The vertex form equation x = -1(y + 6)2 - 10 can be written as
x = -1[y - (-6)]2 + (-4)
Comparing the above equation and x = a(y - k)2 + h,
h = -4 and k = -6
Vertex of the parabola :
(h, k) = (-4, -6)
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