Problem 1 :
Let f(x) = 3x + 2 and g(x) = 5x. Find (f ∘ g) and (g ∘ f).
Problem 2 :
Let f(x) = 2x2 - 3 and g(x) = 4x. Find (f ∘ g) and (g ∘ f).
Problem 3 :
Let f(x) = x + 3 and g(x) = x2 - 9. Find (f ∘ g) and (g ∘ f).
Problem 4 :
Let f(x) = 2x - 1, g(x) = 3x and h(x) = x2 + 1.
Compute the following :
(i) f ∘ g(-3)
(ii) f ∘ h(7)
(iii) (g ∘ h)(24)
(iv) f{g[h(2)]}
Problem 5 :
Let f(x) = log10x and g(x) = 10x. Find (f ∘ g) and (g ∘ f).
1. Solution :
f(x) = 3x + 2 and g(x) = 5x
f ∘ g :
f ∘ g = f[g(x)]
= f(5x)
= 3(5x) + 2
= 15x + 2
g ∘ f :
g ∘ f = g[f(x)]
= g(3x + 2)
= 5(3x + 2)
= 15x + 10
2. Solution :
f(x) = 2x2 - 3 and g(x) = 4x
f ∘ g :
f ∘ g = f[g(x)]
= f(4x)
= 2(4x)2 - 3
= 2(42x2) - 3
= 2(16x2) - 3
= 32x2 - 3
g ∘ f :
g ∘ f = g[f(x)]
= g(2x2 - 3)
= 4(2x2 - 3)
= 8x2 - 12
3. Solution :
f(x) = x + 3 and g(x) = x2 - 9
f ∘ g :
f ∘ g = f[g(x)]
= f(x2 - 9)
= (x2 - 9) + 3
= x2 - 9 + 3
= x2 - 6
g ∘ f :
g ∘ f = g[f(x)]
= g(x + 3)
= (x + 3)2 - 9
= (x + 3)(x + 3) - 9
= x2 + 3x + 3x + 9 - 9
= x2 + 6x
4. Solution :
f(x) = 2x - 1, g(x) = 3x and h(x) = x2 + 1
(i) f ∘ g(-3) :
f ∘ g(-3) = f[g(-3)]
= f[3(-3)]
= f(-9)
= 2(-9) - 1
= -18 - 1
= -19
(ii) f ∘ h(7) :
f ∘ h(7) = f[h(7)]
= f(72 + 1)
= f(49 + 1)
= f(50)
= 2(50) - 1
= 100 - 1
= 99
(iii) g ∘ h(24) :
g ∘ h(24) = g[h(24)]
= g(242 + 1)
= g(576 + 1)
= g(577)
= 3(577)
= 1731
(iv) f{g[h(2)]} :
f{g[h(2)]} = f{g[22 + 1]}
= f{g[4 + 1]}
= f{g(5)}
= f{3(5)}
= f(15)
= 2(15) - 1
= 30 - 1
= 29
5. Solution :
f(x) = log10x and g(x) = 10x
f ∘ g :
f ∘ g = f[g(x)]
= f(10x)
= log1010x
= xlog1010
= x(1)
= x
g ∘ f :
g ∘ f = g[f(x)]
= g(log10x)
= 10log10x
= x
Here f ∘ g = g ∘ f = x.
So f(x) and g(x) are inverse to each other.
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