Inverse Variation :
If an increase (↑) [decrease (↓)] in one quantity produces a proportionate decrease (↓) [increase (↑)] in another quantity, then we say that the two quantities are in inverse variation.
Equation of Inverse Variation :
Direct variation can be represented by the equation.
y = k/x
Here the variable 'k' is known as the constant of variation, and it cannot equal to zero.
Example 1 :
Assume that y varies inversely with x. If y = 1 when x = 6, find y when x = 3.
Solution :
Equation of inverse variation :
y = k/x ----(1)
In order to find the value of k in the equation, we need to apply the values of x and y in the equation.
1 = k (6)
1 = 6k
Divide by 6 on both sides
1/6 = 6k/6
1/6 = k
k = 1/6
By applying the value of k in the (1)st equation, we get
y = 6/x
Equation of inverse variation is y = 6/x.
From this we need to find the value of y, when x = 3.
y = 6/3 ===> 2
Hence the value of y = 2.
Example 2 :
Assume that y varies inversely with x. If y = 50 when x = 40, find x when y = 250.
Solution :
Equation of inverse variation :
y = k/x ----(1)
In order to find the value of k in the equation, we need to apply the values of x and y in the equation.
50 = k/40
Multiply by 40 on both sides,
50(40) = (k/40) x 40
2000 = k
k = 2000
By applying the value of k in the (1)st equation, we get
y = 2000/x
Equation of inverse variation is y = 2000/x.
From this we need to find the value of x, when y = 250.
250 = 2000/x
Multiply by "x" on both sides
250x = 2000
Divide by 250 on both sides
250x/250 = 2000/250
x = 8
Hence the value of x = 8
Example 3 :
Assume that y varies inversely with x. If y = 50 when x = 8, find y when x = 200.
Solution :
Equation of inverse variation :
y = k/x ----(1)
In order to find the value of k in the equation, we need to apply the values of x and y in the equation.
50 = k/8
Multiply by 8 on both sides,
50(8) = (k/8) x 8
400 = k
k = 400
By applying the value of k in the (1)st equation, we get
y = 400/x
Equation of inverse variation is y = 400/x.
From this we need to find the value of y, when x = 200.
y = 400/200
y = 2
Hence the value of y is 2.
Example 4 :
Assume that y varies inversely with x. If y = 2 when x = 2, find y when x = 3.
Solution :
Equation of inverse variation :
y = k/x ----(1)
In order to find the value of k in the equation, we need to apply the values of x and y in the equation.
2 = k /2
Multiply by 2 on both sides,
2(2) = (k/2) x 2
4 = k
k = 4
By applying the value of k in the (1)st equation, we get
y = 4/x
Equation of inverse variation is y = 4/x.
From this we need to find the value of y, when x = 3.
y = 4/3
Hence the value of y is 4/3.
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