Question :
Find the derivative of √x with respect to x.
or
Given y = √x, find dy/dx, where x > 0.
Solution :
y = √x
Write the square root as exponent 1/2.
y = x1/2
Find the derivative on both sides with respect to x using power rule of derivative. That is, in x1/2, bring the exponent 1/2 in front of x and subtract 1 from the exponent 1/2.
Therefore, the derivative √x is
We got that the derivative of √x is 1/(2√x).
Using chain rule, we can explain the derivative of √x.
That is, the derivative of √x is 1/(2√x). So, far we have completed the derivative only for √x, further, we have to find the derivative of the stuff inside the square root, that is x, by chain rule.
Example 1 :
Find dy/dx, if y = √(mx), where m is a constant.
Solution :
Example 2 :
Find dy/dx, if y = √(5x).
Solution :
Example 3 :
Find dy/dx, if y = √(x3).
Solution :
Example 4 :
Find dy/dx, if y = √(x3 + 5x2 - 6x - 5).
Solution :
Example 5 :
Find dy/dx, if y = √sinx.
Solution :
Example 5 :
Find dy/dx, if y = √cosx.
Solution :
Example 5 :
Find dy/dx, if y = √tanx.
Solution :
Example 5 :
Find dy/dx, if y = √lnx.
Solution :
Example 5 :
Find dy/dx, if y = √5.
Solution :
We know that 5 is a constant. So, √5 is also a constant. Since the derivative of a constant is zero, the derivative √5 is zero.
y = √5
dy/dx = 0
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