In this section, you will learn the fundamental laws of logarithms.
There are three fundamental laws of logarithms.
Law 1 :
Logarithm of product of two numbers is equal to the sum of the logarithms of the numbers to the same base.
That is,
loga(mn) = logam + logan
Law 2 :
Logarithm of the quotient of two numbers is equal to the difference of their logarithms to the same base.
That is,
loga(m/n) = logam - logan
Law 3 :
Logarithm of a number raised to a power is equal to the power multiplied by the logarithm of the number to the same base.
That is,
loga(mn) = nlogam
Problem 1 :
Find the logarithm of 64 to the base 2√2.
Solution :
Write 64 as in terms of 2√2.
64 = 26
64 = 24+2
64 = 24 ⋅ 22
64 = 24 ⋅ [(√2)2]2
64 = 24 ⋅ (√2)4
64 = (2√2)4
Then,
log2√264 = log2√2(2√2)4
log2√264 = 4log2√2(2√2)
log2√264 = 4(1)
log2√264 = 4
Problem 2 :
Find the value of log√264.
Solution :
log√264 = log√2(2)6
log√264 = 6log√2(2)
log√264 = 6log√2(√2)2
log√264 = 6 ⋅ 2log√2(√2)
log√264 = 12 ⋅ 2(1)
log√264 = 12
Problem 3 :
Find the value of log(0.0001) to the base 0.1.
Solution :
log0.1(0.0001) = log0.1(0.1)4
log0.1(0.0001) = 4log0.10.1
log0.1(0.0001) = 4(1)
log0.1(0.0001) = 4
Problem 4 :
Find the value of log (1/81) to the base 9.
Solution :
log9(1/81) = log91 - log981
log9(1/81) = 0 - log9(9)2
log9(1/81) = -2log99
log9(1/81) = -2(1)
log9(1/81) = -2
Problem 5 :
Find the value of log(0.0625) to the base 2.
Solution :
log2(0.0625) = log2(0.5)4
log2(0.0625) = 4log2(0.5)
log2(0.0625) = 4log2(1/2)
log2(0.0625) = 4(log21 - log22)
log2(0.0625) = 4(0 - 1)
log2(0.0625) = 4(-1)
log2(0.0625) = -4
Problem 6 :
Find the value of log(0.3) to the base 9.
Solution :
log9(0.3) = log9(1/3)
log9(0.3) = log91 - log93
log9(0.3) = 0 - log93
log9(0.3) = - log93
log9(0.3) = - 1 / log39
log9(0.3) = - 1 / log332
log9(0.3) = - 1 / 2log33
log9(0.3) = - 1 / 2(1)
log9(0.3) = -1/2
Problem 7 :
Given log2 = 0.3010 and log3 = 0.4771, find the value of log6.
Solution :
log6 = log(2 ⋅ 3)
log6 = log2 + log3
Substitute the values of log2 and log3.
log6 = 0.3010 + 0.4771
log6 = 0.7781
Problem 8 :
If 2logx = 4log3, then find the value of 'x'.
Solution :
2logx = 4log3
Divide each side by 2.
logx = (4log3) / 2
logx = 2log3
logx = log32
logx = log9
x = 9
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