PRODUCT OF SUM AND DIFFERENCE OF TWO BINOMIALS

Consider the following sum and difference of two binomials.

(a + b) and (a - b)

Product of sum and difference of the above two binomials :

(a + b)(a - b) = (a + b)(a - b)

= a ⋅ a + a(-b) + b ⋅ a + b(-b)

= a2 - ab + ab + b2

= a2 - b2

Therefore,

(a + b)(a - b) = a2 - b2

or

a2 - b2 (a + b)(a - b)

Example 1 : 

Multiply. 

(x + 5)(x - 5)

Solution :

Use the rule for (a + b)(a - b). 

(a + b)(a - b)  =  a2 - b2

Identify a and b : a = x and b = 5. 

(x + 5)(x - 5)  =  x2 - 52

=  x2 - 25

Example 2 : 

Multiply. 

(x2 + 2y)(x2 - 2y)

Solution :

Use the rule for (a + b)(a - b). 

(a + b)(a - b)  =  a2 - b2

Identify a and b : a = x2 and b = 2y. 

(x2 + 2y)(x2 - 2y)  =  (x2)2 - (2y)2

=  x4 - 4y2

Example 3 : 

Multiply. 

(8 + z)(8 - z)

Solution :

Use the rule for (a + b)(a - b). 

(a + b)(a - b)  =  a2 - b2

Identify a and b : a = 8 and b = z. 

(8 + z)(8 - z)  =  (8)2 - (z)2

=  64 - z2

Example 4 : 

Multiply. 

(3 + 2z2)(3 + 2z2)

Solution :

Use the rule for (a + b)(a - b). 

(a + b)(a - b)  =  a2 - b2

Identify a and b : a = 3 and b = 2z2

(3 + 2z2)(3 + 2z2)  =  (3)2 - (2z)2

=  9 - 4z2

Example 5 : 

Multiply. 

(a2 + b2)(a2 - b2)

Solution :

Use the rule for (a + b)(a - b). 

(a + b)(a - b)  =  a2 - b2

Identify a and b : a = a2 and b = b2

(a2 + b2)(a2 - b2)  =  (a2)2 - (b2)2

=  a4 - b4

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