SUM AND DIFFERENCE OF SQUARES OF TWO BINOMIALS

Expand the square of the binomial (a + b)2 using FOIL method :

(a + b)2 = (a + b)(a + b)

(a + b)2 = a ⋅ a + ab + ab + b ⋅ b

(a + b)2 = a2 + 2ab + b2

From the above working, it is clear that the expansion of (a + b)2 is equal to sum of the squares of the two terms a and b and two times the product of the two terms a and b.

Expand the square of the binomial (a - b)2 using FOIL method :

(a - b)2 = (a - b)(a - b)

(a - b)2 = a ⋅ a + a(-b) - b(a) + (-b)(-b)

(a - b)2 = a2 - ab - ab - b2

(a - b)2 = a2 - 2ab + b2

The following expansions of the squares of two binomials are considered to be algebraic identities.

(a + b)2 = a2 + 2ab + b2

(a - b)2 = a2 - 2ab + b2

It will be helpful to remember the above two algebraic identities to solve problems on expanding the square of a binomial.

Sum of the Squares of Two Binomials

(a + b)2 + (a - b)2 :

= (a2 + 2ab + b2) + (a2 - 2ab + b2)

= a2 + 2ab + b2 + a2 - 2ab + b2

Combine the like terms by grouping.

= (a2 + a2) + (2ab - 2ab) + (b2 + b2)

= 2a2 + 0 + 2b2

= 2a2 + 2b2

= 2(a2 + b2)

Therefore,

(a + b)2 + (a - b)2 = 2(a2 + b2)

Difference of the Squares of Two Binomials

(a + b)2 - (a - b)2 :

= (a2 + 2ab + b2) - (a2 - 2ab + b2)

= a2 + 2ab + b2 - a2 + 2ab - b2

Combine the like terms by grouping.

= (a2 - a2) + (2ab + 2ab) + (b2 - b2)

= 0 + 2ab + 0

= 2ab

Therefore,

(a + b)2 - (a - b)2 = 2ab

Solved Problems

Example 1 :

Simplify :

(2x + 3y)2 + (2x - 3y)2

Solution :

Using (a + b)2 + (a - b)2 = 2(a2 + b2),

(2x + 3y)2 + (2x - 3y)22[(2x)2 + (3y)2]

2(22x2 + 32y2)

2(4x2 + 9y2)

= 8x2 + 18y2

Example 2 :

Simplify :

(2x + 3y)2 - (2x - 3y)2

Solution :

Using (a + b)2 - (a - b)2 = 2ab,

(2x + 3y)2 - (2x - 3y)22(2x)(3y)

= 12xy

Example 3 :

Evaluate :

1012 + 992

Solution :

1012 + 992 = (100 + 1)2 + (100 - 1)2

Using (a + b)2 + (a - b)2 = 2(a2 + b2),

= 2(1002 + 12)

= 2(10000 + 1)

= 2(10001)

= 20002

Example 4 :

Evaluate :

1012 - 992

Solution :

1012 - 99= (100 + 1)2 - (100 - 1)2

Using (a + b)2 - (a - b)2 = 2ab,

= 2(100)(1)

= 200

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