DIFFICULT SAT MATH QUESTIONS

Question 1 :

Triangle ABC shown below is an isosceles triangle with AB = AC and BC = 48. The ratio of DE to DF is 5 : 7. What is the length of DC?

(A) 12           (B) 20           (C) 24           (D) 28

difficult-sat-math-questions.png

Answer :

In the triangle ABC shown above,

m∠E = m∠F = 90°

Since triangle ABC above is isosceles with AB = AC,

m∠B = m∠C

By Angle-Angle (AA) similarity postulate, triangles BED and CFD are similar.

DB/DC = DE/DF

Given : DE/DF = 5/7.

DB/DC = 5/7

DC/DB = 7/5

5(DC) = 7(DB) ----(1)

Given : BC = 48.

BC = 48

DB + DC = 48

DB = 48 - DC

Substitute (48 - DC) for DB in (1).

5(DC) = 7(48 - DC)

5(DC) = 336 - 7(DC)

12(DC) = 336

DC = 28

The correct answer choice is (D).

Question 2 :

To cut a lawn, Allan charges a fee of $15 for his equipment and $8.50 per hour spent cutting a lawn. Taylor charges a fee of $12 for his equipment and $9.25 per hour spent cutting a lawn. If x represents the number of hours spent cutting cutting a lawn, what are all the values of x for which Taylor's total charge is greater than Allan's total charge? 

(A) x > 4

(B) 3 ≤ x ≤ 4

(C) 4 ≤ x ≤ 5

(D) x < 3

Answer :

The variable x represents the number of hours spent cutting cutting a lawn

Given : Allan charges a fee of $15for his equipment and $8.50 per hour spent cutting a lawn.

Allan's total charge = 8.50x + 15

Given : Taylor charges a fee of $12 for his equipment and $9.25 per hour spent cutting a lawn.

Taylor's total charge = 9.25x + 12

We have to find the value of x for which Taylor's total charge is greater than Allan's total charge.

Taylor's total charge > Allan's total charge

9.25x + 12 > 8.50x + 15

Subtract 8.50x from both sides.

0.75x + 12 > 15

Subtract 12 from both sides.

0.75x > 3

Divide both sides by 0.75.

x > 4

The correct answer choice is (A).

Question 3 :

The lengths of the three sides of a triangle are different prime numbers. If two of the sides have lengths 3 and 11, which of the following could be the length of the third side?

I. 7

II. 13

III. 17

(A) I only

(B) II only

(C) I and II only

(D) I, II and III only

Answer :

We have to use Triangle Inequality Theorem to solve this question. That is, sum of the lengths of any two sides of a triangle is always greater than the length of the third side.

Statement I :

If you consider 7 as the length of the third side, then the lengths of the three sides of the triangle are

3, 11 and 7

Verify Triangle Inequality Theorem for the above three side lengths of the triangle.

3 + 11 > 7 (True)

11 + 7 > 3 (True)

3 + 7 > 11 (False)

Statement I is incorrect.

Statement II :

If you consider 13 as the length of the third side, then the lengths of the three sides of the triangle are

3, 11 and 13

Verify Triangle Inequality Theorem for the above three side lengths of the triangle.

3 + 11 > 13 (True)

11 + 13 > 3 (True)

3 + 13 > 11 (True)

Statement II is correct.

Statement III :

If you consider 13 as the length of the third side, then the lengths of the three sides of the triangle are

3, 11 and 17

Verify Triangle Inequality Theorem for the above three side lengths of the triangle.

3 + 11 > 17 (False)

11 + 17 > 3 (True)

3 + 17 > 11 (True)

Statement III is incorrect.

The correct answer choice is (B).

Question 4 :

Victor wants to sell 3 watches, each at the same price. After negotiating with customers, however, he ends up selling one at a 30% discount, one at a 20% discount and one at a 10% discount. If Victor sold the watches for a total of $240, how much money did he lose by giving the discounts?

(A) $45

(B) $60

(C) $75

(D) $90

Answer :

Let x be the actual selling price of each watch.

After 30% discount, selling price of the watch :

= (100 - 30)% of x

= 70% of x

= 0.7x

After 20% discount, selling price of the watch :

= (100 - 20)% of x

= 80% of x

= 0.8x

After 10% discount, selling price of the watch :

= (100 - 10)% of x

= 90% of x

= 0.9x

Given : After discounts, Victor sold the watches for a total of $240.

0.7x + 0.8x + 0.9x = 240

2.4x = 240

Divide both sides by 2.4.

x = 100

The actual selling price (without discount) of each watch is $100.

If Victor had not given given discounts, then the total money he would have received :

= 3 x $100

= $300

Amount of money Victor lost by  giving the discounts :

= $300 - $240

= $60

The correct answer choice is (D).

Question 5 :

If √x + √y = 4√y, where x > 0 and y > 0, what is x in terms of y?

(A) 16y

(B) 9y

(C) 6y

(D) 4y

Answer :

√x + √y = 4√y

Subtract √y from both sides.

(√x + √y) - √y = (4√y) - √y

√x + √y - √y = 4√y - √y

√x = 3√y

Square both sides.

(√x)2 = (3√y)2

x = (3)2(√y)2

x = 9y

The correct answer choice is (B).

Note :

Simplification of (4√y - √y) is similar to (4y - y).

We know that 

4y - y = 3y

So,

4√y - √y = 3√y

Question 6 :

What is one possible value of x for which the function g above is undefined?

Answer :

We know that the square root of a negative number is imaginary or undefined. 

If (x - 1)(x - 2) is negative or (x - 1)(x - 2) < 0, then g(x) is undefined.

So, we have to solve the inequality (x - 1)(x - 2) < 0 to find one possible value of x for which g(x) is undefined.

(x - 1)(x - 2) < 0

Assume the above inequality as equation and solve for x.

(x - 1)(x - 2) < 0

x - 1 = 0  or  x - 2 = 0

x = 1  or  x = 2

Mark the above two values of x on the real number line.

intervals.png

We get the following three intervals from the above number line.

(-, 1), (1, 2) and (2, +)

Check each of the above three intervals with the inequality (x - 1)(x - 2) < 0.

(-, 1) :

Take a random value in the interval (-, 1)  and substitute for x into the inequality.

Let x = 0 ∈ (-, 1).

(0 - 1)(0 - 2) < 0

(-1)(-2) < 0

2 < 0 (False)

(1, 2) :

Take a random value in the interval (1, 2)  and substitute for x into the inequality.

Let x = 1.5 ∈ (1, 2).

(1.5 - 1)(1.5 - 2) < 0

(0.5)(-0.5) < 0

-0.25 < 0 (True)

(1, +) :

Take a random value in the interval (1, +)  and substitute for x into the inequality.

Let x = 2 ∈ (1, +).

(2 - 1)(2 - 2) < 0

(1)(0) < 0

0 < 0 (False)

When x ∈ (1, 2), (x - 1)(x - 2) < 0 and g(x) is undefined.

One possible value for x in the interval (1, 2) is 1.5 for which g(x) is undefined.

Question 7 :

satquestion33.png

In the xy-plane above, O is the center of the circle, and the measure of ∠AOB is π/a radians. What is the value of a?

Answer :

In the diagram above, draw perpendicular line AM to x-axis.

satquestion33a.png

OB = √3 and AB = 1

In the right ΔOAB,

tan∠AOB = opposite side/adjacent side

tan∠AOB = AB/OB

tan∠AOB = 1/√3

tan∠AOB = 1/√3

From trigonometric ratio table, we have

tan30° = 1/√3

or

tan(π/6) = √3

Then,

∠AOB = π/6

Given : The measure of ∠AOB is π/a radians.

π/a = π/6

Take reciprocal on both sides.

a/π = 6/π

Multiply both sides by π.

a = 6

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