MULTIPLYING ALGEBRAIC EXPRESSIONS EXAMPLES

Problem 1 :

2y ∙ 3

Solution :

Given , 2y ∙ 3

By multiplying signs  =  +

multiplying coefficients  =  2(3)  ==>  6

Multiplying variables  =  y

So the answer is 6y.

Problem 2 :

6x ∙ 2x

Solution :

Given , 6x ∙ 2x

By multiplying signs  =  +

multiplying coefficients  =  6(2)  ==>  12

Multiplying variables  =  x ∙ x  ==>  x²

So, the answer is 12x².

Problem 3 :

3ac ∙ 4a

Solution :

Given , 3ac ∙ 4a

By multiplying signs  =  +

multiplying coefficients  =  3(4)  ==>  12

Multiplying variables  =  ac ∙ a  ==>  a²c

=  12a² c

Problem 4 :

2st ∙ 3st

Solution :

Given , 2st ∙ 3st

=  6s²t²

Problem 5 :

a² ∙ 2a²

Solution :

Given , a² ∙ 2a²

=  2a⁴

Problem 6 :

4y ∙ (2y)²

Solution :

Given , 4y ∙ (2y)²

=  4y ∙ 4y²

=  16y³

Problem 7 :

3a ∙ (2a)²

Solution :

Given , 3a ∙ (2a)²

=  3a ∙ 4a²

= 12a³

Problem 8 :

9b³ ∙ 4b²

Solution :

Given , 9b³ ∙ 4b²

=  36b⁵

Problem 9 :

(-x) ∙ 3x

Solution :

Given , (-x) ∙ 3x

=  -3x²

Problem 10 :

(-2x) ∙ (-x)

Solution :

Given , (-2x) ∙ (-x)

=  2x²

Problem 11 :

(-3x) ∙ 4x²

Solution :

Given , (-3x) ∙ 4x²

=  -12x³

Problem 12 :

(-x²) ∙ 5x²

Solution :

Given , (-x²) ∙ 5x²

=  5x⁴

Problem 13 :

8x ∙ (-x³)

Solution :

Given , 8x ∙ (-x³)

=  -8x⁴

Problem 14 :

3x² ∙ (-x)³

Solution :

Given , 3x² ∙ (-x)³

=  -3x⁵

Problem 15 :

2d² . (-d)²

Solution :

Given , 2d² . (-d)²

=  2d⁴

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