1. Solve for x : 8x = 56.
2. Solve for y : y/4 = 7.
3. When 7 is multiplied by a number, we get 42. Find the number.
4. John had some candies. He shared the candies equally to his 3 kids. If each kid had received 7 candies, how many candies did John have ?
5. The product of two numbers is 20. If one number is 8, find the other number.
1. Answer :
8x = 56
Since we are trying to solve for "x", we have to get rid of 8 which is multiplied by "x".
To get rid of 8, we have to divide by 8 on both sides.
8x / 8 = 56/8
x = 7
Hence, the value of "x" is 7.
2. Answer :
y / 4 = 7
Since we are trying to solve for "y", we have to get rid of 4 which divides y in the above equation.
To get rid of 4, we have to multiply by 4 on both sides.
(y / 4) x 4 = 7 x 4
y = 28
Hence, the value of "y" is 28.
3. Answer :
Let "x' be the required number.
According to the question, we have
7x = 42
Here, 7 is multiplied by x. To get rid of 7, we have to divide by 7 on both sides and solve the equation as explained below. .
7x / 7 = 42/7
x = 6
Hence, the value of "x" is 6.
4. Answer :
Let "m' be the no. of candies that John initially .
According to the question, we have
m/3 = 7
Here 3 divides m. To get rid of 3, we have to multiply by 3 on both sides and solve the equation as explained below.
(m/3) x 3 = 7 x 3
m = 21
Hence, John initially had 21 candies.
5. Answer :
Let "x' be the other number.
According to the question, we have
8x = 20
Here, 8 is multiplied by x. To get rid of 8, we have to divide by 8 on both sides and solve the equation as explained below. .
8x / 8 = 20/8
x = 2.5
Hence, the other number is 2.5.
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