SOLVING AN EQUATION WITH VARIABLES ON BOTH SIDES

Equations with variables on both sides can be used to compare costs of real-world situations. To solve these equations, use inverse operations to get the variable terms on one side of the equation.

The following steps will be useful to solve equations with variables on both sides.

Step 1 :

To solve the equations with variables on both sides, we have to get rid of the variable on one of the sides using addition/subtraction.

Step 2 :

After getting the variable on only one side of the equation, isolate the variable on that side using the binary operations (addition, subtraction, multiplication and division) to get rid of the numbers around the variable.

Example 1 :

Solve for a :

-3 + 5a = 4a - 10

Solution :

-3 + 5a = 4a - 10

Subtract 4a from both sides.

-3 + a = -10

Add 3 to both sides.

a = -7

Example 2 :

Solve for x :

3x - 1 = x + 5

Solution :

3x - 1 = x + 5

Subtract x from both sides.

2x - 1 = 5

Add 1 to both sides.

2x = 6

Divide both sides by 2.

x = 3

Example 3 :

Solve for y :

1 - 3y = 3y + 1

Solution :

1 - 3y = 3y + 1

Subtract 3y from both sides.

1 - 6y = 1

Subtract 1 from both sides.

6y = 0

Divide both sides by 2.

y = 0

Example 4 :

Solve for n :

4n - 1 = 6n + 8 - 8n + 15

Solution :

4n - 1 = 6n + 8 - 8n + 15

Simplify the expression on the right side.

4n - 1 = -2n + 23

Add 2n from both sides.

6n - 1 = 23

Add 1 to both sides.

6n = 24

Divide both sides by 6.

n = 4

Example 5 :

Solve for x :

1 - x = 16 - 4x

Solution :

1 - x = 16 - 4x

Add 4x to both sides.

1 - x = 16 - 4x

1 + 3x = 16

Subtract 1 from both sides.

3x = 15

Divide both sides by 3.

x = 5

Example 6 :

Solve for z :

-40 + 2z = 4z - 8(z + 8)

Solution :

-40 + 2z = 4z - 8(z + 8)

Use the distributive property on the right side.

-40 + 2z = 4z - 8z - 64

Simplify the expression on the right side.

-40 + 2z = -4z - 64

Add 4z to both sides.

-40 + 6z = -64

Add 40 to both sides.

6z = -24

Divide both sides by 6.

z = -4

Example 7 :

Solve for x :

7x - 8(-x + 7) = -16 + 7x

Solution :

7x - 8(-x + 7) = -16 + 7x

Use the distributive property on the left side.

7x + 8x - 56 = -16 + 7x

Simplify the expression on the left side.

15x - 56 = -16 + 7x

Subtract 7x from both sides.

8x - 56 = -16

Add 56 to both sides.

8x = 40

Divide both sides by 8.

x = 5

Example 8 :

Solve for r :

-6(2r - 2) = -8r + 40

Solution :

-6(2r - 2) = -8r + 40

Use the distributive property on the left side.

-12r + 12 = -8r + 40

Add 8r to both sides.

-4r + 12 = 40

Subtract 12 from both sides.

-4r = 28

Divide both sides by -4.

r = -7

Example 9 :

Solve for x :

2(1 + 6x) + 2(3 - 6x) = 7x - 5x

Solution :

2(1 + 6x) + 2(3 - 6x) = 7x - 5x

Use the distributive property on the left side.

2 + 12x + 6 - 12x = 7x - 5x

Simplify the expressions on both sides.

8 = 2x

Divide both sides by 2.

4 = x

Example 10 :

David's Rental Car charges an initial fee of $20 plus an additional $30 per day to rent a car. Alex's Rental Car charges an initial fee of $36 plus an additional $28 per day. For what number of days is the total cost charged by both of them the same ?

Solution :

Let x be the number of days for which the total cost charged by both of them is same.

Step 1 : 

Write an expression using x representing the total cost of renting a car from David’s Rental Car.

Total cost = Initial fee + cost for x days

Total days = 20 + 30x

Step 2 : 

Write an expression using x representing the total cost of renting a car from Alex’s Rental Car.

Total cost = Initial fee + cost for x days

Total days = 36 + 28x

Step 3 : 

We have assumed that the total cost charged by both of them is same for x number of days.

So, we have

20 + 30x = 36 + 28x

Step 4 : 

Solve for x : 

20 + 30x = 36 + 28x

Subtract 28x from each side. 

20 + 2x = 36

Subtract 20 from each side. 

2x = 16

Divide each side by 2. 

x = 8

So, the total cost charged by both of them is same for 8 days.

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