Consider the function F(x) as shown below.
Using the Second Fundamental Theorem of Calculus, the formula to find derivative of F(x) is
F'(x) = (b)'f(b) - (a)'f(a)
In each case, use the Second Fundamental Theorem of Calculus to finf F'(x).
Problem 1 :
Solution :
Let f(t) = t2 - 2t.
F'(x) = (x)'f(x) - (-2)'f(-2)
F'(x) = (1)f(x) - (0)f(-2)
F'(x) = (1)(x2 - 2x) - 0
F'(x) = x2 - 2x
Problem 2 :
Solution :
F'(x) = (x)'f(x) - (1)'f(1)
F'(x) = (1)f(x) - (0)f(1)
Problem 3 :
Solution :
F'(x) = (x)'f(x) - (1)'f(1)
F'(x) = (1)f(x) - (0)f(1)
Problem 4 :
Solution :
F'(x) = (x)'f(x) - (1)'f(1)
F'(x) = (1)f(x) - (0)f(1)
F'(x) = (1)(√x csc x) - 0
F'(x) = √x csc x
Problem 5 :
Solution :
F'(x) = (4x)'f(4x) - (1)'f(1)
F'(x) = (4)f(4x) - (0)f(1)
F'(x) = 4cot(4x) - 0
F'(x) = 4cot(4x)
Problem 6 :
Solution :
F'(x) = (x2)'f(x2) - (1)'f(1)
F'(x) = (2x)f(x2) - (0)f(1)
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